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解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9(5)(

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解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9(5)(x+2)^2=(2x+1)^2
(6)9(x+3)^2=(2x-5)^2
快哦
解下列方程:(1)x^2=36 (2)(2x-1)^2=25 (3)2x^2+7x=0 (4)x^2-6x=-9(5)(
(1 ) x^2 - 36=0 (x-6)(x+6) =0 x-6=0 x+6 =0 x1 =6 x2 =-6
(2))(2x-1)^2 - 25 = 0 [( 2x-1)-5 ] [(2x-1)+5 ]=0 ( 2x-1)-5 =0 ( 2x-1)+5 =0
x1=3 x2=-2
(3) x(2x+7)=0 x=0 2x+7=0 x1=0 x2= -7/2
(4) x^2-6x+9=0 (x - 3)^2 =0 x - 3 = 0 x1=x2 = 3
(5) (x+2)^2 -(2x+1)^2 = 0 [(x+2)-(2x+1)]*[(x+2)+(2x+1)]=0 (1-x)(3x+3)=0 1-x=0 3x+3 =0
x1=1 x2=-1
(6)9(x+3)^2 - (2x-5)^2=0 [3(x+3) - (2x - 5)][3(x+3) +(2x - 5)] =0 (x + 14)(5x + 4) = 0
x + 14 =0 5x + 4 =0
x1= -14 x2 = -4/5