大师作文网化简2sin^2(x)sin^2(φ)+2cos^2(x)cos^2(φ)-cos2(x)cos^2(φ)
来源：学生作业帮 编辑：大师作文网作业帮 分类：数学作业 时间：2024/11/10 23:30:37
化简2sin^2(x)sin^2(φ)+2cos^2(x)cos^2(φ)-cos2(x)cos^2(φ)
据:cos2(x)=cosx^2-sinx^2=2cosx^2-1得:
2sin^2(x)sin^2(φ)+2cos^2(x)cos^2(φ)-cos2(x)cos^2(φ)
=2sin^2(x)sin^2(φ)+cos^2(φ)
=(2sin^2(x)-1)*sin^2(φ)+sin^2(φ)+cos^2(φ)
=(sin^2(x)-cos^2(x))*sin^2(φ)+1
=-cos2(x)*(1-cos2φ)/2+1
2sin^2(x)sin^2(φ)+2cos^2(x)cos^2(φ)-cos2(x)cos^2(φ)
=2sin^2(x)sin^2(φ)+cos^2(φ)
=(2sin^2(x)-1)*sin^2(φ)+sin^2(φ)+cos^2(φ)
=(sin^2(x)-cos^2(x))*sin^2(φ)+1
=-cos2(x)*(1-cos2φ)/2+1
化简2sin^2(x)sin^2(φ)+2cos^2(x)cos^2(φ)-cos2(x)cos^2(φ)
化简 cos^2(x)*sin^2(x)-sin^2(x)
化简 cos^(2)(x)*sin^(2)(x)-sin^(2)(x)
cos 2x /sin^2 x*cos^2 x不定积分
2cos x (sin x -cos x)+1
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
(sin^2x+cos^2x )(sin^2x-cos^2x)怎么得sin^2x-cos^2x?
化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)
化简 1/2cos x-根号3/2sin x 根3sin x+cos x
∫sin(x) cos^2(x)dx
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
求导f(x) = cos(3x) * cos(2x) + sin(3x) * sin(2x).