1.(2x-1)(4x²+2x+1))
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
解方程:1.x/x+1-1=3/(x+1)(x-2) 2.3/x+2+1/x=4/x²+2x 3.2/3+x/
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
(4x³)²×[x³-x(2x-1)]
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x
(x+1)/(x²+3x+2)+(x²-2x)/(x²-4)
x²-2x分之x+2-x²-4x+4分之x-1
x+2/x²-2x-x-1/x²-4x+4计算
(x+2)/x(x-2)-(x-1)/x²-4x+4=几,