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已知函数f(x)=(1+cotx)sin²x+msin(x+π/4)× sin(x-π/4)

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已知函数f(x)=(1+cotx)sin²x+msin(x+π/4)× sin(x-π/4)
(1)当m=0时,求f(x)在区间[ π/8 ,3π/4 ]上的取值范围
(2)当tanα=2时,f(α)=3/5,求m的值
已知函数f(x)=(1+cotx)sin²x+msin(x+π/4)× sin(x-π/4)
(1)当m=0时,f(x)=(1+cotx)sin²x =sin²x+sinxcosx=[1-cos(2x)]/2+sin(2x)/2
=1/2-sin(2x-π/4)/√2
∵x∈[π/8,3π/4] ∴2x-π/4∈[0,5π/4] ∴sin(2x-π/4)∈[0,1]
∴f(x)∈[(1-√2)/2,1/2]
(2)f(α)=(1+cotα)sin²α+msin(α+π/4)×sin(α-π/4)
=(1+cotα)sin²α-m/2cos(2α)
tanα=2 ∴cotα=1/2 cos^2α=1/5 sin^2α=4/5 cos(2α)=-3/5
∴f(α)=(1+cotα)sin²α-m/2cos(2α)=3/2×4/5+3m/10=3/5
∴m=-2