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当x=2011,y=-2012时,

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当x=2011,y=-2012时,
求代数式(x的4次方-y的4次方/x²-2xy+y²)²÷(x²+y²/y-x)²的值         
当x=2011,y=-2012时,
[(x^4-y^4)/(x²-2xy+y²)]²÷[(x²+y²)/(y-x)]²
=(x^4-y^4)²/(x-y)^4÷[(x²+y²)²/(x-y)²]
=(x^4-y^4)²/(x-y)^4×(x-y)²/(x²+y²)²
=(x²+y²)²(x²-y²)²/(x-y)²/(x²+y²)²
=(x²-y²)²/(x-y)²
=(x+y)²(x-y)²/(x-y)²
=(x+y)² 将x=2011,y=-2012代入
=(-1)²=1