求极限 lim(2^x+3^x -2)/x 当X趋近于0
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求极限 lim(2^x+3^x -2)/x 当X趋近于0
不是负无穷吧。答案写是一个不等于0的常数。
不是负无穷吧。答案写是一个不等于0的常数。
由洛必达法则,
lim (x→0) (2^x +3^x -2) /x
= lim (x→0) [(2^x) (ln 2)+(3^x) (ln 3) ] /1
= ln6.
= = = = = = = = =
如果没学洛必达法则,但学了等价无穷小量,见解法2.
解法2:因为 lim (t→0) (e^t -1) /t =1,
令 t =x (ln 2),
则 x = t /(ln2).
所以 t→0 时,x→0.
所以 lim (x→0) (2^x -1) / [ x (ln2) ] =1,
所以 lim (x→0) (2^x -1) /x =ln2.
同理,lim (x→0) (3^x -1) /x =ln3.
所以 lim (x→0) (2^x +3^x -2) /x
= lim (x→0) (2^x -1) /x +lim (x→0) (3^x -1) /x
= ln6.
= = = = = = = = =
解法3:(导数的定义)
令 f(t) =2^t,
则 f'(t) =(2^t) (ln2),
所以 f'(0) =ln2,
即 lim (x→0) (2^x -2^0) /(x -0) =ln2,
即 lim (x→0) (2^x -1) /x =ln2.
同理,lim (x→0) (3^x -1) /x =ln3.
所以 lim (x→0) (2^x +3^x -2) /x
= lim (x→0) (2^x -1) /x +lim (x→0) (3^x -1) /x
= ln6.
lim (x→0) (2^x +3^x -2) /x
= lim (x→0) [(2^x) (ln 2)+(3^x) (ln 3) ] /1
= ln6.
= = = = = = = = =
如果没学洛必达法则,但学了等价无穷小量,见解法2.
解法2:因为 lim (t→0) (e^t -1) /t =1,
令 t =x (ln 2),
则 x = t /(ln2).
所以 t→0 时,x→0.
所以 lim (x→0) (2^x -1) / [ x (ln2) ] =1,
所以 lim (x→0) (2^x -1) /x =ln2.
同理,lim (x→0) (3^x -1) /x =ln3.
所以 lim (x→0) (2^x +3^x -2) /x
= lim (x→0) (2^x -1) /x +lim (x→0) (3^x -1) /x
= ln6.
= = = = = = = = =
解法3:(导数的定义)
令 f(t) =2^t,
则 f'(t) =(2^t) (ln2),
所以 f'(0) =ln2,
即 lim (x→0) (2^x -2^0) /(x -0) =ln2,
即 lim (x→0) (2^x -1) /x =ln2.
同理,lim (x→0) (3^x -1) /x =ln3.
所以 lim (x→0) (2^x +3^x -2) /x
= lim (x→0) (2^x -1) /x +lim (x→0) (3^x -1) /x
= ln6.
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