4xy+1-4x²-y²

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/13 01:53:25

4xy+1-4x²-y²
8x³+4x²-2x-1

4xy+1-4x²-y²
=1 - (4x²+y²-4xy)
= 1 ² - (2x-y)²
=(1+2x-y)(1-2x+y)
8x³+4x²-2x-1
=(8x³+4x²)- (2x+1)
=4x²(2x+1) - (2x+1)
= (4x²-1)(2x+1)
=(2x+1)² (2x-1)

x²+xy/(x-4y)(x+y),其中x=4,y=-1 已知X²+Y²+X²Y²-4XY+1=0 求:（X-Y)^2008-(XY)^2 【分解因式】 x²-xy+4分之1y² x²y-2xy²+y³ a（x 因式分解:4x²y+4xy²+xy² 化简并求值 xy-2{xy-[3x²y-(xy²+0.5xy)]+4x²y},其中x=1, 已知2X-3√xy-2y=0(x>0)求2x²+xy-9y²分之x²+4xy-16y 3x²y+xy²-[2xy²-4x²y+（x²y-2xy²） (2x²y-3xy²)-3(x²y-2xy²)+2（x²y-4xy&# 因式分解：x²-y²+4xy 4x²y-1/2{x²y-[5x²y-2(2xy²+1/4xy)]}+3xy&# 已知x²-3xy+4x=3,y²+xy-4y+7=0,则xy-1/2(x²+y² (-x-2y)(x²-2xy+4y²)