若x<y<0,则x2−2xy+y2+x2+2xy+y2=( )
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若x<y<0,则
x
∵x<y<0,
∴x-y<0,x+y<0. ∴ x2−2xy+y2= (x−y)2=|x-y|=y-x. x2+2xy+y2= (x+y)2=|x+y|=-x-y. ∴ x2−2xy+y2+ x2+2xy+y2=-2x, 故选C.
若x<y<0,则x2−2xy+y2+x2+2xy+y2=( )
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