x+y+z=3(1) x+2y+3z=6(2) 2x+y+2z=5(3)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x/2=y/3=z/5 x+3y-z/x-3y+z
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
3道高数题,1,函数F(x,y,z)=(e^x) * y * (z^2) ,其中z=z(x,y)是由x+y+z+xyz=
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
x+y+z=2 x-3y+2z=1 2x+2y+z+5 要具体步骤..
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
解方程组:x+y+z=4,x+y+2z=5,3x+y-z=6
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
5x+3y+2z=2011 4x+6y+7z=2012 求x+y+z