(2/3x-2/x+y(x+y/3x-x-y))÷x-y/x,其中5x+3y=0
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(2/3x-2/x+y(x+y/3x-x-y))÷x-y/x,其中5x+3y=0
(2/3x-2/x+y(x+y/3x-x-y))÷x-y/x
=(2/3x-2/x+y(y/3x-y))÷x-y/x
=(2/3x-2/x+y²/3x-y²)÷x-y/x
=2/3-2/x²+y²/3x²-y²/x-y/x
=2/3+y²/3x²-2/x²-y²/x-y/x
=2/3+(y²-6)/3x²-y(y-1)/x
5x+3y=0时5x=-3y即x=-3y/5代入
=2/3+(y²-6)/3(-3y/5)²-y(y-1)/(-3y/5)
=2/3+(y²-6)/3(9y²/25)+y(y-1)/(3y/5)
=2/3+25(y²-6)/27y²+5(y-1)/3
再问: ((2/3x)-(2/x+y)((x+y/3x)-x-y))÷(x-y/x) 没理解错吧?
再答: 怎么又加上括号了?就算加上括号,((x+y/3x)-x-y)去掉括号后两个x还是抵消掉了呀?=(y/3x-y)对不对?
再问: 虽然感觉你的不对 但还是给我带来了解题的灵感 谢了 分给了
=(2/3x-2/x+y(y/3x-y))÷x-y/x
=(2/3x-2/x+y²/3x-y²)÷x-y/x
=2/3-2/x²+y²/3x²-y²/x-y/x
=2/3+y²/3x²-2/x²-y²/x-y/x
=2/3+(y²-6)/3x²-y(y-1)/x
5x+3y=0时5x=-3y即x=-3y/5代入
=2/3+(y²-6)/3(-3y/5)²-y(y-1)/(-3y/5)
=2/3+(y²-6)/3(9y²/25)+y(y-1)/(3y/5)
=2/3+25(y²-6)/27y²+5(y-1)/3
再问: ((2/3x)-(2/x+y)((x+y/3x)-x-y))÷(x-y/x) 没理解错吧?
再答: 怎么又加上括号了?就算加上括号,((x+y/3x)-x-y)去掉括号后两个x还是抵消掉了呀?=(y/3x-y)对不对?
再问: 虽然感觉你的不对 但还是给我带来了解题的灵感 谢了 分给了
(2/3x-2/x+y(x+y/3x-x-y))÷x-y/x,其中5x+3y=0
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