大师作文网已知r 满足[r+19/100]+[r+20/100]+[r+21/100]+...+[r+91/100]=546．求[
![已知r 满足[r+19/100]+[r+20/100]+[r+21/100]+...+[r+91/100]=546．求[](/uploads/image/z/5792050-10-0.jpg?t=%E5%B7%B2%E7%9F%A5r+%E6%BB%A1%E8%B6%B3%5Br%2B19%2F100%5D%2B%5Br%2B20%2F100%5D%2B%5Br%2B21%2F100%5D%2B...%2B%5Br%2B91%2F100%5D%3D546%EF%BC%8E%E6%B1%82%5B)
已知r 满足[r+19/100]+[r+20/100]+[r+21/100]+...+[r+91/100]=546．求[
若实数r使得[r+19/100]+[r+20/100]+…+[r+91/100]=546,求[100r]
已知r =100,求r 方+2r +1分之+r+1分之r-1+r的值
200\100=50+r\r
r
r等于100求r的平方加2r加1分之2r加2加r加1分之r减1
〔r+0.19〕+〔r+0.20〕+……〔r+0.91〕=546,求〔100r〕
R²=（R-200)²+100²怎么解
R*sin{100/R}=75 求半径R 题目为弧长200 弦长150 求半径
已知实数p.q.r满足p+q+r=26,1/p+1/q+1/r等于31,求p/q+q/r+r/p+p/r+r/q+q/p
{R}=R
设R={,},试求r(R),s(R)和t(R)