一道关于巧算的数学题`
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一道关于巧算的数学题`
(1).(2+1)(2方+1)(2的4次方+1)(2的8次方+1)+1
(2).2006/(2006方-2005*2007)
那个*就是乘号,
(1).(2+1)(2方+1)(2的4次方+1)(2的8次方+1)+1
(2).2006/(2006方-2005*2007)
那个*就是乘号,
(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^4-1)(2^4+1)(2^8+1)+1
=(2^8-1)(2^8+1)+1
=2^16-1+1
=2^16
=65536
2006/(2006^2-2555*2007)
=2006/(2006^2-(2006-1)*(2006+1))
=2006/(2006^2-(2006^2-1))
=2006/1
=2006
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^4-1)(2^4+1)(2^8+1)+1
=(2^8-1)(2^8+1)+1
=2^16-1+1
=2^16
=65536
2006/(2006^2-2555*2007)
=2006/(2006^2-(2006-1)*(2006+1))
=2006/(2006^2-(2006^2-1))
=2006/1
=2006