[log3(4)+log根下3(2)][log2(9)+log4(根3)]
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[log3(4)+log根下3(2)][log2(9)+log4(根3)]
题目是(log以3为底4的对数+log以根3为底2的对数)(log以2为底9的对数+log以4为底根3的对数)
题目是(log以3为底4的对数+log以根3为底2的对数)(log以2为底9的对数+log以4为底根3的对数)
[log3(4)+log根下3(2)][log2(9)+log4(根3)]
=[lg4/lg3+lg2/lg根下3][lg9/lg2+lg根3/lg4]
=[2lg2/lg3+2lg2/lg3][2lg3/lg2+1/4lg3/lg2]
=4lg2/lg3*9/4lg3/lg2
=9
再问: 答案是对的,解法没看明白。 题目是(log以3为底4的对数+log以根3为底2的对数)(log以2为底9的对数+log以4为底根3的对数)
再答: 主要是利用换底公式 loga(b)=lgb/lga
=[lg4/lg3+lg2/lg根下3][lg9/lg2+lg根3/lg4]
=[2lg2/lg3+2lg2/lg3][2lg3/lg2+1/4lg3/lg2]
=4lg2/lg3*9/4lg3/lg2
=9
再问: 答案是对的,解法没看明白。 题目是(log以3为底4的对数+log以根3为底2的对数)(log以2为底9的对数+log以4为底根3的对数)
再答: 主要是利用换底公式 loga(b)=lgb/lga
[log3(4)+log根下3(2)][log2(9)+log4(根3)]
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
(log2(5)+log4(125))×log3(2)/log根号3(5)
(log2 5+log4 125)log3 2/ log根号3 5
[log2(3)+log4(9)][log3(4)+log9(2)]等于
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
(log2 3+log4 27)(log3 4+log27 16)
log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(k+2) 怎么证
(log2^5+log4^125)(log3^2)/(log(根号3)^5 要具体的过程,
(log2(5)+log4(125))(log3(2)/log√3(5))怎么解?
log 2 3 * log3 4 * log4 5 *log5 2 化简
log2(20)-log2(5)+2log3(2)×log4(3)