大师作文网9、10题,谢谢啦高一数学
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9、10题,谢谢啦高一数学
补充第九题：
x=1时,f( 1-1 ) + f(1) = 1 => f(1)=1-f(0)=1;
x=1时,f( 1/3 ) = 1/2f(1) => f(1/3) = 1/2;
x=1/2时,f(1 - 1/2) +f(1/2) =1 => f(1/2) = 1/2 ;
f(x)非减 => f(1/2) >= f(5/12) >= f(1/3) => 1/2 >= f(5/12) >= 1/2 所以 f(5/12)=1/2;
所以f( 1/3 )+f(5/12) = 1/2 + 1/2 =1;
x=1时,f( 1-1 ) + f(1) = 1 => f(1)=1-f(0)=1;
x=1时,f( 1/3 ) = 1/2f(1) => f(1/3) = 1/2;
x=1/2时,f(1 - 1/2) +f(1/2) =1 => f(1/2) = 1/2 ;
f(x)非减 => f(1/2) >= f(5/12) >= f(1/3) => 1/2 >= f(5/12) >= 1/2 所以 f(5/12)=1/2;
所以f( 1/3 )+f(5/12) = 1/2 + 1/2 =1;