log2^8-16^1/2=_______?感激不尽!

log2^8-16^1/2=_______?感激不尽! (log2 9)/(log2 8) = 2/3(log2 3) 2^log2 (3) × log2 (1/8) + 2lg3 解方程log2(2-x)=log2(x-1)+1 log2 (x + 3) + log2(x + 2) = 1 解方程：log2(x+4)+log2(x-1)=1+log2(x+8) log2(根号下7/48)+log2(12)-1/2log2(42)-1=? log2 SQR(7/48)+log2 12 -1/2log2 48 log2 SQR(7/48)+log2 12 -1/2log2 42 已知1/16≤2^(-x)≤1/2,求函数y=log2(2x)*log2(x/8)的最大值和最小值. log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^ 在等比数列{an}中,a1=2,a4=16,令bn=1/｛log2(an).log2[a(n+1)]｝