(2)(x-1)²-(x-1)-6=0 (3)4x²-4√2x+1=0 (4)(3x-4)²
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(2)(x-1)²-(x-1)-6=0 (3)4x²-4√2x+1=0 (4)(3x-4)²=9x
(2)(x-1)²-(x-1)-6=0 (3)4x²-4√2x+1=0 (4)(3x-4)²=9x-12
(2)(x-1)²-(x-1)-6=0 (3)4x²-4√2x+1=0 (4)(3x-4)²=9x-12
(x-1)²-(x-1)-6=0
((x-1)-3)((x-1)+2)=0
∴x-1=3,x1=4;x-1=-2,x=-1.
4x²-4√2x+1=0
4x²-4√2x+2=1
(2x-√2)²=1
2x-√2=±1
∴2x-√2=1,x1=(1+√2)/2;2x-√2=-1,x2=(√2-1)/2
(3x-4)²=9x-12
9x²-24x+16=9x-12
9x²-33x+28=0
(3x-4)(3x-7)=0
∴3x-4=0,x1=4/3;3x-7=0,x2=7/3
再问: 谢谢啦,已解决
再答: 给个采纳吧,亲
((x-1)-3)((x-1)+2)=0
∴x-1=3,x1=4;x-1=-2,x=-1.
4x²-4√2x+1=0
4x²-4√2x+2=1
(2x-√2)²=1
2x-√2=±1
∴2x-√2=1,x1=(1+√2)/2;2x-√2=-1,x2=(√2-1)/2
(3x-4)²=9x-12
9x²-24x+16=9x-12
9x²-33x+28=0
(3x-4)(3x-7)=0
∴3x-4=0,x1=4/3;3x-7=0,x2=7/3
再问: 谢谢啦,已解决
再答: 给个采纳吧,亲
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