y=1/x^2,则dy

y=1/x^2,则dy 设y=ln(1+x^2)则dy= y=ln(1+2x) 则dy= 设y-x-1/2sinx,则dx/dy= 从(dx)/(dy)=1/y '导出：(d^2x)/(dy^2)=-y''/(y')^3 dy/dx,y=(1+x+x^2)e^x y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy dy/dx=x(1+y^2)/y通解 y=[sin(x^4)]^2,则dy/dx=?,dy^2/dx^2=?,dy/d(x^2)=? 若y=x^2+x , 则dy= dy/dx-2y/(x+1)=(x+1)^2 dy/dx-2y/(1+x)=(x+1)^3