大师作文网[(a+2b)^2×(2b-a)^3]÷(2b+a)^5÷(a-2b)^8
![[(a+2b)^2×(2b-a)^3]÷(2b+a)^5÷(a-2b)^8](/uploads/image/z/8877135-39-5.jpg?t=%5B%28a%2B2b%29%5E2%C3%97%282b-a%29%5E3%5D%C3%B7%282b%2Ba%29%5E5%C3%B7%28a-2b%29%5E8)
化简：{[(2a-b)/(a+b)]-[b/(a-b)]}÷[(a-2b)/(a+b)]
[（a+2b)(a-2b)-(2a-b)²+(3a-b)(3a-5b)]÷2a
计算(a-b)^m(a-b)[2(b-a)]^3[(b-a)^5]^2÷(a-b)^m=
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
化简 (a²+b²/a²-b²-a-b/a+b)÷2ab/(a-b)(a+b)&
8a+2b+(5a - b) (5a-3b) -3 (a平方 - 2b)
[(a+2b)^2×(2b-a)^3]÷(2b+a)^5÷(a-2b)^8
已知2a-b+1的绝对值+(3a+3/2b)^=0,求(b^/a+b)÷{[(b/a-b)+1][a-(a^/a+b)]
计算：(b/a)^2÷（a/b)-b^3/a^3(a-b) ÷ 1/a-b
(a+b/a-b)²×2a-2b/3a+3b÷ab/a²-b²
a-b+2b²/a+b
（a+b分之2a-b - a-b分之b）÷ a+b分之a-2b