z=sinx/sin(x+y)偏导怎么求?

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/11 04:02:18

z=sinx/sin(x+y)偏导怎么求?
如题,sinx/sin(x+y)偏导

az/ax=(cosxsin(x+y)-sinxcos(x+y))/sin^2(x+y)
=sin(x+y-x)/sin^2(x+y)
=siny/sin^2(x+y)
az/ay=sinx*(-1/sin^2(x+y))*cos(x+y)
=-sinxcos(x+y)/sin^2(x+y)

z=sinx/sin(x+y)偏导怎么求? 求函数z=sinx+siny+sin(x+y)(0 已知x,y,z属于(0,派/2),sin^2x+sin^2y+sin^2z=1,求(sinx+siny+sinz)/(c 证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+ 三角不等式证明证明sin(x+y)+sin(y+z)+sin(z+x)>sinx+siny+sinz+sin(x+y+z 求函数z=(x+y)sin(x-y)的偏导数∂z/∂x,∂z/∂y 设y=sinx²+sin²x,求y' 求sin(x+y)=sinx+siny的导数求函数y=sin^2x+sinx的值域求函数y=sin²x+sinx的值域 y=sin²x*sinx²求导~求过程求y=sin(x-π/3)sinx最大值