(2014•东昌府区二模)化简a+1a
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/30 01:31:49
(2014•东昌府区二模)化简
a+1 |
a
原式=
a+1 (a−1)2+ a−1+2 a−1 = a+1 (a−1)2+ a2−1 (a−1)2 = a+1+a2−1 (a−1)2 = a(a+1) (a−1)2. 故答案是: a(a+1) (a−1)2.
(2014•东昌府区二模)化简a+1a
化简a(a+2)-(a-1)(a+1)
化简:a/a-1÷(a-1/a)等于
化简:(2a+1/a²-1)*a²-2a+1/a²-a-(1/a+1)
化简[a^2+a/a^2-1+(a^2-a分之根号下a^2-2a+1)
化简(9-a²)/a²+6a+9÷(a²-3a)/a+3+1/a
化简:(a+1)(a
(2+1/a-1-1/a+1)÷(a-a/1-a²)化简
a+1+a(a+1)+a(a+1)的平方+…+a(a+1)的2013次方+a(a+1)的2014次方=?
化简(1 - 1/a-1)÷a²-4a+4/a²-a
(1)化简:-a²-a³-a²+a³-a²
化简:3a-[5a-(2a-1)]=
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