先化简x²-1分之x²-2x÷(x-1-x+1分之2x-1)
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/20 12:19:20
x^2-1=(x+1)(X-1)x^2-2x+1=(x-1)^2第一项为(X+1)/(x-1)第二项为-x(x+1)so最后-1/x(x-1)
x满足方程x-1分之x+x分之1=1得x²+x-1=x²-x得x=1/2(x+1分之3-x+1)÷x+1分之x²-2x=[(x+1)分之(4-x²)]×[(x&
x+2分之x-x+2分之x平方+2x+1除以x-1分之x平方-1=[x/(x+2)-(x²+2x+1)/(x+2)]÷(x²-1)/(x-1)=[(x-x²-2x-1)/
先化简,再求值:(x平方-1)分之(3x-3)÷(x+1)分之(3x)-(x+1)分之1,其中x=2=3(x-1)/(x+1)(x-1)×(x+1)/(3x)-1/(x+1)=1/x-1/(x+1)=
(3-x分之x-1)平方÷(x平方-6x+9分之9-x平方)平方*x平方-2x+1分之6+2x=[(x-1)/(3-x)]²÷[(9-x²)/(x²-6x+9)]
{[(x+2)/(x^2-2x)]-[(x-1)/(x-2)]}/[(x+3)/x]={[(x+2)/(x^2-2x)]-[(x^2-x)/(x^2-2x)]}*[x/(x+3)]=[(-x^2+2x
你写的看不懂分子分母的代数式用括号括起来否则分不出来先通分【((x-2)(x+2)-x(x-1))/x(x+2)(x+2)】(x+2)/(x-4)=(x-4)/x(x+2)(x-4)=1/x(x+2)
[(x-2)/(x^2+2x)-(x-1)/(x^2+4x+4)]÷(x-4)/(x+2)=[(x-2)/x(x+2)-(x-1)/(x+2)^2]*(x+2)/(x-4)=(x-2)/x(x-4)-
(x^2-2x分之x+2-x^2-4x+4分之x-1)/x分之4-x=[(x+2)/(x(x-2)-(x-1)(x-2)^2]/(4-x)/x=[(x+2)(x-2)-x(x-1)/x(x-2)^2]
x分之4再问:有过程吗他那个是x-1分之1-x+1分之1的再答:[1/(x-1)-1/(x+1)]/[x/(2x方-2)]=[2/(x方-1)]*[2(x方-1)/x]=(2*2)/x=x/4
[(x-1)/x-(x-2)/(x+1)]÷[(2x^2-x)/(x^2+2x+1)]=[(x-1)(x+1)-x(x-2)]/x(x+1)÷[x(2x-1)/(x+1)^2=(2x-1)/x(x+1
(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)=(x²-x-6+x-3)/x(x-3)=
原式=[(x-1)/(x+1)+2x/(x²-1)]÷1/(x²-1)=[(x-1)/(x+1)+2x/(x²-1)]×(x²-1)=(x²-1)×(
x^2-x-1=0x^2=x+1(x分之x-1—x+1分之x-2)÷x的平分+2x+1分之2x的平分-x=((x-1)(x+1)-x(x-2))/x(x+1)÷(x(2x-1)/(x+1)^2)=((
(x²-1分之x-3)÷(x²+2x+1分之x²-2x-3)-(x+1分之1)=(x-3)/(x+1)(x-1)×(x+1)²/(x-3)(x+1)-1/(x+
(x²-1分之x²+1)-(x-1分之x-2)÷(x分之x-2)=(x+1)(x-1)分之(x²+1)-(x-1)分之(x-2)*(x-2)分之x=(x+1)(x-1)分
[(x+2)/x-(x-1)/(x-2)]÷(x-4)/x=[1+2/x-1-1/(x-2)]×x/(x-4)=(x-4)/x(x-2)×x/(x-4)=1/(x-2)=1/(3-2)=1这是我在静心
原式=[2x(x+1)/(x+1)(x-1)-x(x-1)/(x-1)²]÷x/(x+1)=[2x/(x-1)-x/(x-1)]×(x+1)/x=x/(x-1)×(x+1)/x=(x+1)/