22÷2x=64
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原式=(3x²+3x-x²+x)/(x+1)(x-1)*x(x²-1)/x²(x²-4)=(2x²+4x)/(x+1)(x-1)*(x+1)
2x=86x=43
x-四分之一x=八分之三0.75x=八分之三x=1/2X-0.8X=220.2x=22x=22/0.2x=110三分之二X+二分之一X=427/6x=42x=42*6/7x=36
负36.375
(x+2/x²-2x-x-1/x²-4x+4)÷x-4/x={(x+2)(x-2)/[x(x-2)²]-x(x-1)/[x(x-2)²]}·x/(x-4)={(
(0.5+x)+x=9.8÷22x+0.5=4.92x=4.9-0.52x=4.4x=2.2
注意:本题x=2时题目没意义,应该舍去(这是很多学生错误所在)这里x只能取根号2-1
(x^2-1)=(x+1)*(x-1)(x^2+x)=x(x+1)通分x-(2x-1)/x=((x^2-2x+1)/x=(x-1)^2/x带回写成分式后发现约掉一个x,一个(x+1),一个(x-1)化
3x+x/3=180+306x+x=210*37x=630x=90
原式=2x(x-2)/(x+2)×x(x+2)/(x-2)²×3(x-2)/x=6x当x=√3/2时原式=3√3
/>(4X+2)/X+【4(X-5)-2】/(X-5)=【(X-4)-2】/(X-4)+【7(X+1)+2】/(X+1)4+2/X+4-2/(X-5)=1-2/(X-4)+7+2/(X+1)8+2/X
152-x=(22+x)×2152-x=44+2x2x+x=152-443x=108x=108/3x=36再问:谢谢,你做的很对。再答:希望采纳,谢谢
先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-
x^3-2x^2+4x/x^2-4x+4÷x^2-2x+4/x-2=x(x²-2x+4)/(x-2)²÷(x-2)/(x²-2x+4)=x(x²-2x+4)/(
2x+22-x=40x=40-22x=18
2*(22-x)-4x=244-2x-4x=244-6x=244-2=6x42=6xx=7
(5x+14)÷(x+2)==(5x+14)/(x+2)最简形式,不要再算了再问:[(x+2)²+2(x+2)(x-2)-3(x+2)(x-3)]÷(x+2)=?化简再答:[(x+2)&su
1,应该是x是几次幂就有几个根吧,所以应该是7+2=9个2.-7.036622145,-6.489288572,-6.200988153,-4.734373320,-4.289168546,-2.77
11x+42-2x=100-9x-2211x-2x+9x=100-22-4218x=36x=2
=[3/(x+1)-(x-1)]÷(x²-2x)/(x+1)=[3/(x+1)-(x-1)(x+1)/(x+1)]÷x(x-2)/(x+1)=[3-(x+1)(x-1)]/(x+1)÷x(x