2x+(22-x)=40
2x+(22-x)=40
(x/x-1)+(5x-2)/x*x-x=1 求x(有图)
2*【x+(x+40)】=400
f(x)=x²+3x|x-2|
(4x+2)/x+(4x-22)/(x-5)=(x-6)/(x-4)+(7x+9)/(x+1)
f(x)=-x^2+2x(x>0) 0(x=0) x^2-2x(x
解方程(x-2)X(x的平方-6x-9)=x(x-5)X(x-3)
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
解方程:(x-8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)
(x)-2x·x-x-2x+1=0求x的值,
1/4x+5+1/2【x-(1/4x+5)】-5+40=x
5x+3=x-4,4y+11=22,11x+68-2x=100-9x,0.1x/0.2-(0.27x+0.18)/0.0