3x的平方减5x减2分之1减3的差加2x方的和-搜答案-大师作文网

我不太确定我的理解和你的意思是否完全一样.1/5x^2-4x+x/2-6x^2+3-x/3-1=-29/5x^2-23/6x+2分别对二次项、一次项的系数和常数进行加减运算,就得到合并同类项的结果.

如图所示

有歧义啊啊!再问：？再答：你这说的太不清楚了，建议写下来拍照再问：再问：再问：再答：第一个是x+1/x+2再答：第二个是1/a+2再答：第三个太麻烦再问：再问：对不对？再答：对再答：分呢！

[3x/(x+1)-x/(x-1)]÷(x-2)/(x^2-1)=(2x^2-4x)/(x^2-1)÷(x-2)/(x^2-1)=2x(x-2)/(x-2)=2x

（x+1）/x²-2x²/(x+1)=1两边乘x²(x+1)(x+1)²-2x^4=x²(x+1)x²+2x+1-2x^4=x^3+x

是：x分之(x²+3)-(x²+3)分之4x=3吧!!设k=x分之(x²+3),那么：(x²+3)分之x=k分之1所以原方程可化为：k-k分之4=3上式两边同乘

x^2-3x+1=0x+1/x=(x^2+1)/x=(x^2-3x+1+3x)/x=(0+3x)/x=3x^2+1/x^2=(x+1/x)^2-2=3^2-2=7

首先计算(x+3)/(x^2-1)乘以（x^2-2x+1）/(x^2+4x+3),分解因式可以得到(x+3)/(x+1)(x-1)乘以(x-1)^2/(x+3)(x+1),约分后等于(x-1)/(x+

x减1分之x平方减1,化简为x+1得2005+1=2006第二问不太清楚

3/(x-1)^2-3X/(x-1)^2=(3-3X)/(x-1)^2=3(1-X)/(1-X)^2=3/(1-x)同分母相减,在提公因式后约分再问：(1-X)^2怎么来的？？再答：(1-X)^2=(

定义域：x²-3x≠0x(x-3)≠0x≠0且x≠3很高兴为您解答,【the1900】团队为您答题.请点击下面的【选为满意回答】按钮,

2x/(x^2-4)=2x/((x-2)*(x+2))最简公分母是x*(x-2)*(x+2)1/(x-1)-1/(x+1)-2/(x^+1)=(x+1-x+1)/(x^2-1)-2/(x^+1)=2/

1：2分之3X的平方-{-2分之1X平方}+{-2X平方}=3x²/2+x²/2-2x²=4x²/2-2x²=2x²-2x²=02

原式=[3x/(x-1)-x/(x+1)]×[(x²-1)/x]={3x(x+1)/[(x-1)(x+1)]-x(x-1)/[(x-1)(x+1)]}×[(x-1)(x+1)/x]=[3x(

[(x^2-2x+1)/x^2]÷(x^2-1)*[(x^2+x)/(x^2-3x+2)]=[(x-1)^2/x^2]÷[(x+1)(x-1)]*[x(x+1)/(x-1)(x-2)]=(x-1)^2

3x/(x^2-1)+(x^2-1)/2x=5/2令m=x/(x^2-1)3m+1/2m=5/26m^2+1=5m6m^2-5m+1=0(3m-1)(2m-1)=0m=1/3或m=1/2当m=1/3时

x=1/3或x=-1

/>原式=x-1/(1-x)-(x^2-3x+2)/(x^2-1)=x+1/(x-1)-(x^2-3x+2)/[(x+1)(x-1)]=[x(x+1)(x-1)]/[(x+1)(x-1)]+(x+1)