C语言,输入三个字符,并使其从小到大输出,用函数实现数据的交换
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#include#includevoidmain(){printf("请数输入一个字符:");charch=getchar();if(ch>='a'&&ch='A'&&ch='0'&&ch
voidmain(){intx,y,z,temp;scanf("%d",&x);scanf("%d",&y);scanf("%d",&z);if(x再问:你的完全正确
#includeintmain(){chara,b;a=getchar();scanf("%c",&b);printf("a=%c\n",a);printf("b=%c\n",b);return0;}
1.floatpi(){floatmin=1;floatpi=0;floatpi_1=0;floati=1;while(min>0.01){pi_1=pi+1/i;if(i>0)
#includevoidmain(){inta,b,c;intd,e,f,sum;printf("请输入三个整数:\n");scanf("%d,%d,%d",&a,&b,&c);//分号放错位置了su
你所写的代码是正确的,想要查看,请用这个:#includeintmain(){charch;scanf("%c",&ch);if(ch>='A'&&ch
不对,实质上这种情况该用char类型,并判断,因为int可输入多位,例如输入11,12,14你这种算法就不能反向输出
////第一个程序#include <stdio.h>int main(){char ch;int count = 0;i
两次调用swap(交换位置)函数就可以,swap函数在谭浩强的C语言上有的.
#include<stdio.h>int main(){int a,b,c,d,t; printf("please enter
a+b>cabs(a-b)再问:能编个完整的给我吗?谢谢。新手,看不懂啊……不胜感激再答:#includeinta,b,c;scanf("%d,%d,%d",&a,&b,&c);if(a>0&&b>0
#include#includevoidmain(){intnum;printf("input\t:");scanf("%d",&num);printf("%d\t%d\n",num,abs(
我可以给你写出代码,#includeintmain(){inti,j,k,n;scanf("%d",&n);for(i=1;i
第一个#includevoidmain(){chara;scanf("%c",&a);if((a>'a')&&(a
#include#includeintmain(){inta,b,c;floatp,s;scanf("%d%d%d",&a,&b,&c);if(a+b>c&&a+c>b&&b+c>a){p=(a+b+
#includevoidmain(){\x09intyear;\x09printf("请输入年份:");\x09scanf("%d",&year);\x09if((year%4==0&&year/10
#include#definetrue1voidprint(charcType,intiRow,intiColumn,charcMark){inti,j;if(cType=='A'){for(i=0;
#include"stdio.h"voidmain(){charch;scanf("%c",&ch);if(ch>='0'&&ch='a'&&ch='A'&&ch
1:#includeintmain(){inta[10],i,*p,j,temp;for(i=0;i
#includevoidmain(){inta,b,c,d;printf("Pleaseinput3numbers,example,[1,2,3]:\n");scanf("%d,%d,%d",&a,&