log8 四分之一
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/04 14:22:42
备注:第一个()内是“底数”,第二个()内是“真数”log8底9*log3底32=log(3的平方)(2的三次方)*log(2的五次方)(3)=3/2log(3)(2)*1/5log(2)(3)=3/
(log8^27)/(log4^9)=log2^3(3^3)/log2^2(3^2)=3/3*log2(3)/2/2*log2(3)=log2(3)/log2(3)=1
=(log(2,3)/2+log(2,3)/3)*(log(3,2)+1/3-?)log(a,b)=ln(b)/ln(a)
log(4)2=1/2log(8)2=1/3即log42+log82=1/2+1/3=5/6
4根号2是2^(5/2)原式=log8(5/2)=log2(5/2)/log28=(log25-1)/3这才是正确答案,呵呵
log4(3)+log8(3)=(1/2)log2(3)+(1/3)log2(3)=(5/6)log2(3)
log8(9)=1og2^3(3^2)=2/3*log2(3)∴log8(9)/log2(3)=2/3*1=2/3
运用换底公式:log827除以log23=(ln27/ln8)/(ln3/ln2)=(3ln3/3ln2)*(ln2/ln3)=(ln3/ln2)*(ln2/ln3)=1再问:嗯我这块有点小不会有些题
log827*log316=log23*log32*4=4
方法一(log89/log23)=(lg9/lg8)/(lg3/lg2)=(2lg3/3lg2)/(lg3/lg2)=(2/3)*(lg3/lg2)/(lg3/lg2)=2/3方法二(log89/lo
=(lg2/lg3)*(lg9/lg8)(换底)=(lg2*lg9)/(lg3*lg8)=(lg2*2lg3)/(lg3*3lg2)=2/3
六分之五再问:过程,谢啦再答:log4(3)=1/2log2(3)log8(3)=1/3log2(3)故原式=5/6log2(3)Xlog3(2)=5/6
log8(9)/log2(3)=(lg9/lg8)/(lg3/lg2)=[(2lg3)/(3lg2)]/(lg3/lg2)=(2/3)(lg3/lg2)/(lg3/lg2)=2/3再问:you,too
log48=log2^22^3=log22^(3/2)=3/2所以:log84=2/3;所以:log48-log84=3/2-2/3=5/6.
log4(3)+log8(3)=log2(3)/log2(4)+log2(3)/log2(8)=0.5log2(3)+1/3*log2(3)=5/6*log2(3)在高中阶段运算到这一步化为单个对数就
log89=log2^33^2=2/3log23没办法再分析了结果是2/3
这个问题是这样的4=2²=(2^3)^(2/3)=8^(2/3)所以log8(8^(2/3))=2/3前面的是对数运算法则logaM-logaN=loga(M/N)
log2^3+log8^9=log2^3+(2/3)log2^3=(5/3)log2^3
log8(9)*log2(3)=lg9/lg8*lg3/lg2=2/3lg3的平方/lg2的平方
log3(2)=lg2/lg3log5(3)=lg3/lg5log8(5)=lg5/lg8log3(2)*log5(3)*log8(5)=(lg2*lg3*lg5)/(lg3*lg5*lg8)=lg2