计算log8底9*log3底32
计算log8底9*log3底32
log3(2)*log8(9)
log3(2)*log8(9)怎么计算?
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
计算:log8 27*log3 16=
(9/4)^(-1/2)+log8 9*log3 32=
对数运算的题目,已知log8 9=a ,log3 20=b,用a,b表示lg2ps:log8 9为以8为底9的对数
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
log8(9)乘以log3(32)-lg4-2lg5+3+27^(2/3)
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
log8为底25为真数乘以log0.2为底32为真数+9的1/2-log3为底2为真数次方+log根号2减1为底根号下3
2log3底2-log3底32/9+log3底8