(2x-1)2=9(1-2x)怎么解
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/23 12:35:32
x到底等于-21/4(-4x²+2x-8)-(1/2x-1)还是等于1/2[补充一下:9x+6x²-3(x-2/3x²)化简得:6x+8x²]再问:x等于-2再
是这样的:x^5+x^4=x^3(x^2+x)=(x^2+x)[(x^3-1)+1]=(x^2+x)(x^3-1)+x^2+x=[x(x+1)(x-1)](x^2+x+1)+x^2+x=(x^3-x)
1)(x-3)/(x-2)-(x-5)/(x-4)=(x-7)/(x-6)-(x-9)/(x-8)化简得【(x-3)(x-4)-(x-5)/(x-2)】/【(x-2)(x-4)】=【(x-7)(x-8
X除以(X-2)+(X-9)除以(X-7)=(X+1)除以(X-1)+(X-8)除以(X-6)(x-2+2/x-2)+(x-7-2/x-7)=(x-1+2/x-1)+(x-6-2/x-6)1+(2/x
[x-x/(x+1)][(x+1)/(x^2+4x+4)][(x^2-4)/(x^2-2x)]=[x^2/(x+1)][(x+1)/(x+2)^2][(x+2)(x-2)/x(x-2)]=x/(x+2
原式=[(x-1)(3x²+9x+7)-(x+1)(2x²-4x+3)-(x³+x+1)]/(x²-1)=[(3x³+6x²-2x-7)-(
由于【(x+1)-x】/x(x+1)=1/x(x+1)所以1/x(x+1)=1/x-1/(x+1)同理可得:1/(x+1)(x+2)=1/(x+1)-1/(x+2)·····所以原方程可写为:【1/x
[(x+2)+1]/(x+2)-[(x+1)+1]/(x+1)=[(x+4)+1]/(x+4)-[(x+3)+1]/(x+3)1+1/(x+2)-1-1/(x+1)=1+1/(x+4)-1-1/(x+
(x^2+9x)(x^2+9x+18)=68040(x^2+9x)^2+18(x^2+9x)+81=68040+81(x^2+9x+9)^2=261^2x^2+9x+9=2614x^2+36x+36+
两边同时乘以2x(x+1)约分后为2(x-1)(x+1)-2x(1-x)=5x(x-1)化简为2x^2-2-2x+2x^2=5x^2-5xx^2-3x+2=0(x-1)(x-2)=0解得x=1或2
[(x^2)^2-2x^2*x+x^2]-(2x^2+2x+1)=0即(x^2-x)^2-(2x^2-2x)-4x+1=0[(x(x-1))^2-2(x(x-1))+1]-4x=0(x(x-1)-1)
1/x(x+1)+1/(x+1)(x+2)+...+1/(x+8)(x+9)=(1/x-1/x+1)+(1/x+1-1/x+2)+...+(1/x+8-1/x+9)=1/x-1/x+9=9/x(x+9
x(x^2-1)+2x^2*(x+1)-3x*(2x-5)=x(3x^2-4x)-28;x^3-x+2x^3+2x^2-6x^2+15x=3x^3-4x^2-28;14x=-28.x=-2.
(x-1)^3(x+1)(x-2)/(x+4)
题目太多了请分开求助,我好多赚点采纳数哈:)多谢啦4×(0.8-x)=1.40.8-x=1.4÷4=0.35x=0.8-0.35=0.455+2/3x-1/2x=12(2/3x-1/2x)=12-5(
看来是因式分解题目(x+1)(x+2)(x+3)(x+4)+1=(x+1)(x+4)(x+2)(x+3)+1=(x^2+5x+4)(x^2+5x+6)+1=(x^2+5x)^2+10(x^2+5x)+
你题目里面M应该抄错了,应该是(X²+2X+1)(X²-2X+1)M-N=(X²+2X+1)(X²-2X+1)-(X²+X+1)(x²-X+
(x+2/x^2-2x-x-1/x^2-4x+4)/x-4/x=[(x+2)/x(x-2)-(x-1)/(x-2)²]/(x-4)/x=[(x²-4-x²+x)/x(x-
=4*(-27)+64=-44
方程右边的1减到左边来,再同分得到(6x-2)/(x^2-x)=0得到x=1/3这个方程即使两边乘以x^2-x,x的最高次数为2次,也不会出现x^3,你肯定是什么地方弄错了