x-3分2=5分之一解方程
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/20 17:19:40
即1/(x+10)+1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+……+1/(x+9)-1/(x+10)=2所以1/(x+1)=2x+1=1/2x=-1/2
5x-6(-3x-2)(-2+3x)-54(x-3分之一)(x+3分之一)=25x-6(4-9x²)-54(x²-1/9)=25x-24+54²-54x²+6=
互乘得:3*(x-2)=x;3*x-6=x;2*x=6;x=3;
7x=6x-87x-6x=-8x=-83x-2=4x-33x-4x=-3+2x=1x/2-3=x/5x/2-x/5=33x/10=3x=107x+4分之一=9x-1.57x-9x=-1.5-0.252
3x=3/5-1/4x=7/20÷3x=7/60
x=6
/>x=1/81/2x=6 x=122/5x=3/10 x=3/43/4x=3/8 x=1/2 采纳哦
由题意可知:x≠0且x≠-5则原方程可化为:[x(x+5)]分之(x+5-x)=5[x(x+5)]分之5=5[x(x+5)]分之1=1那么:x(x+5)=1x平方+5x=1x平方+5x+25/4=1+
x分之一+5分之3乘以x分之一=3分之2除以61/X+3/5*1/X=(2/3)/61/X+3/5*1/X=1/98/5*1/X=1/98/5*1/X=1/9X=8/5*9=72/5
再问:再问:再答:再答:亲,满意望采纳再问:再问:再答:
1/(x-5)-1/(x-6)=1/(x-8)-1/(x-9)[(x-6)-(x-5)]/[(x-5)(x-6)]=[(x-9)-(x-8)]/[(x-8)(x-9)](-1)/[(x-5)(x-6)
1/x+5+1/x+8=1/x+6+1/x+71/x+5-1/x+6=1/x+7-1/x+8(x+6)/[(x+5)(x+6)]-(x+5)/[(x+5)(x+6)]=(x+8)/[(x+7)(x+8
解题思路:运用等式的性质2,依次等式变形化简可解。解题过程:
1/x(x+1)+1/(x+1)(x+2)+.+1/(x+8)(x+9)=(2x+3)/x(x+9)1/x-1/(x+1)+1/(x+1)1/(x+2)+.+1/(x+8)-1/(x+9)=(2x+3
通分(2x+13)/(x²+13x+40)=(2x+13)/(x²+13x+42)(2x+13)/(x²+13x+40)-(2x+13)/(x²+13x+42)
(1)方程的解x-7分之一+x-1分之一=x-6分之一+x-2分之一(x-7)分之一-(x-2)分之一=(x-6)分之一-(x-1)分之一(x-7)(x-2)分之5=(x-6)(x-1)分之5(x-7
x²+1/x²-3(x+1/x)+2=0(x+1/x)²-3(x+1/x)=0(x+1/x)(x+1/x-3)=0x+1/x=0x²=-1(舍去)x+1/x-3