x^9 x^6 x^3-3
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(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问:第二步那个1是怎么
将x-7/x-9分解成1+2/(x-9)其他分式同理则原方程等价于1/x-9+1/x-5=1/x-6+1/x-81/x-6-1/x-5=1/x-9-1/x-81/(x-5)(x-6)=1/(x-8)(
|x-1|+|x-10|表示数轴上x到1的距离+x到10的距离.显然最小值是9,此时x只要在1到10之间就好.类似的,|x-2|+|x-9|的最小值是7,此时x在2到9之间就好.|x-3|+|x-8|
设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)那么y=a*(x-10);那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a那么y
1)(x-3)/(x-2)-(x-5)/(x-4)=(x-7)/(x-6)-(x-9)/(x-8)化简得【(x-3)(x-4)-(x-5)/(x-2)】/【(x-2)(x-4)】=【(x-7)(x-8
再问:额、不懂再答: 再答:后面的看做一个整体再问:好的吧、谢谢大神再答:回来的话,请采纳再问:啊、突然明白了呢。。。
(X²+3X+9/X²-27)+(6X/9X-X²)-(X-1/6+2X)=X²+3X+9/X²-27+6/9-X²-X+1/6+2X=9/
=x^18+x^15+x^12+x^9+x^6+x^3+1+x^3-1+5-4分解因式把下面的18换成21就是了=(x^18+1)+(x^15+1)+(x^12+1)+(x^9+1)+(x^6+1)+
x(1+2+...+9)=x(9-8-7-...-1)x=0记得采纳啊
是9x-x³原式=(x²+3x+9)/(x-3)(x²+3x+9)-6x/x(x-3)(x+3)-(x-1)/2(x+3)=1/(x-3)-6/(x-3)(x+3)-(x
中间错了原式=(x+2)/(x-3)(x+2)+2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)+2/(x-3)-(x+1)/(x-3)²=3/(x-3)-(x+1)/
(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)=2(x-3)/(x-2)^2X(x+3)^2/(3-x)X(2-x)/(x+3)=2(x-
原式=(x+2)/(x+2)(x-3)-2x/x(x-3)-(x+1)/(x-3)²=1/(x-3)-2/(x-3)-(x+1)/(x-3)²=-1/(x-3)-(x+1)/(x-
原式=[x(x-3)/(x-3)²][(x-5)(x-6)/x(x-5)]-1=[x/(x-3)][(x-6)/x]-1=(x-6)/(x-3)-1=(x-6-x+3)/(x-3)=-3/(
(x+2)/(x^2-x-6)+2x/(x^2-3x)-x/(x^2-6x+9)=(x+2)/[(x-3)(x+2)]+2x/[x(x-3)]-x/[(x-3)^2]=1/(x-3)+2/(x-3)-
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设x^3=a,则题目可变为下式:a^3+a^2+a-14=a^3-8+a^2+a-6=(a-2)(a^2+2a+4)+(a-2)(a+3)=(a-2)(a^2+2a+4+a+3)=(a-2)(a^2+
(X²+3X+9/X²-27)+(6X/9X-X²)-(X-1/6+2X)=X²+3X+9/X²-27+6/9-X²-X+1/6+2X=9/