分式约分:(y+z-x)/{x^2-(y+z)^2}

分式约分:(y+z-x)/{x^2-(y+z)^2} 约分 x²-(y-z)²除以(x+y)²-z² 这是个分式! 分式约分( 1 ) x^2-1分之1-x^2 ( 2 )x^2-(y-z)^2分之(x+y)^2-z^2 (y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y) 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x (x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) 分式约分和通分约分：10x^4 y^3 z/-15x^2 y^4 z^2 m^2-3m/9-m^2通分：2/3a^2与1 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x- 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知x+y-z/z=x-y+z/y=-x+y+z/x,且xyz不等于0,求分式[(x+y)(x+z)(y+z)]/xyz 分式x^2-y^2/(x-y)^2如何约分