解不定式组:(x-1)(x+2)≥(x+3)(x-3)
解不定式组:(x-1)(x+2)≥(x+3)(x-3)
解不等式组 1-二分之一(x+1)≤x+2 ,x(x-1)≥(x+3)(x-3)
x(2x-5)>2x的平方-3x-4 (x+1)(x-3)+8x>(x+5)(x-5)-2 解不等式组
解不等式组5x-1>3(x+1).(1/2x)-1≥3x-(3/2x).x-1<3x+1
[x(x+1)+x平方(x-1)]+(-3x)
(x-1)^3(x+1)(x-2)/(x+4)
(x+1)(x+2)(x+3)(x+4)+1
计算 x(x+3)-(x-1)(x-2)
解方程1/x(x+1)+1/(x+1)(x+2)+...+1/(x+8)(x+9)=2x+3/x(x+9)
解方程:1\x(x+1)+1\(x+1)(x+2)+.+1/(x+8)(x+9)=2x+3\x(x+9)
(x+2/x+1)-(x+4/x+3)-(x+3/x+2)+(x+5/x+4)
解方程:(x-8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3)