计算:log以根号3为底2-log以3为底32/9+log以3为底8-25(log以5为底3)次方
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计算:log以根号3为底2-log以3为底32/9+log以3为底8-25(log以5为底3)次方
log以根号3为底2-log以3为底32/9+log以3为底8-25(log以5为底3)次方
=log3 (2)-log3 (32)+log3 (9)+3log3 (2)-(5²)^[log5 (3)]
=log3 (2)-5log3 (2)+2+3log3 (2)-5^[log5 (9)]
=-log3 (2)+2-9
=-log3 (2)-7
再问: log以根号3为底2怎么变成log3 (2)
再答: log3 (2) 指的就是 log以根号3为底2
=log3 (2)-log3 (32)+log3 (9)+3log3 (2)-(5²)^[log5 (3)]
=log3 (2)-5log3 (2)+2+3log3 (2)-5^[log5 (9)]
=-log3 (2)+2-9
=-log3 (2)-7
再问: log以根号3为底2怎么变成log3 (2)
再答: log3 (2) 指的就是 log以根号3为底2
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