{5x+2y-4z=1① 3x-3y+2z=1② -2x+3y-2z=0③}
{5x+2y-4z=1① 3x-3y+2z=1② -2x+3y-2z=0③}
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x/2=y/3=z/5 x+3y-z/x-3y+z
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-
解方程一;{x+y-z=6,x-3y+2z=1,3x+2y-z=-7.②{3x+4z=7,2x+3y+z=9,5x-9y
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-
1.解下列方程组,①y-2z=1,x+3z=-1,3x-5y+z=21.②x+y+2z=7,x-2y-z=-4,2x+3
三元一次方程求解:①x+2z=3,2x+y=2,2y+z=7.②x+y+z=2,3x-y-4z=5,2x+3y-2z=0
{x+y+z=4 {2y+z=0 {3x+2y-4z=-1