解方程组,√(x+1/y)+√(x-y-2)=4 2x-y+1/y=10
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解方程组,√(x+1/y)+√(x-y-2)=4 2x-y+1/y=10
求高手解答,过程要详细
求高手解答,过程要详细
2x-y+1/y=10
x+1/y+x-y-2=8
设x+1/y=a
x-y-2=b
a+b=4
a^2+b^2=8
b=4-a
a^2+(4-a)^2=8
a^2+a^2-8a+16=8
2a^2-8a+8=0
(a-2)^2=0
a=2
b=4-2=a
√(x+1/y)=2
√(x-y-2)=2
x+1/y=4
x-y-2=4
y=x-6
x+1/(x-6)=4
x(x-6)+1=4(x-6)
x^2-6x+1-4x+24=0
x^2-10x+25=0
(x-5)^2=0
x=5
y=5-6=-1
x+1/y+x-y-2=8
设x+1/y=a
x-y-2=b
a+b=4
a^2+b^2=8
b=4-a
a^2+(4-a)^2=8
a^2+a^2-8a+16=8
2a^2-8a+8=0
(a-2)^2=0
a=2
b=4-2=a
√(x+1/y)=2
√(x-y-2)=2
x+1/y=4
x-y-2=4
y=x-6
x+1/(x-6)=4
x(x-6)+1=4(x-6)
x^2-6x+1-4x+24=0
x^2-10x+25=0
(x-5)^2=0
x=5
y=5-6=-1
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