1+3+5+7+.+21+23+21+19+17+...+7+5+3+1=

1+3+5+7+.+21+23+21+19+17+...+7+5+3+1= 1+3+5+7+···+21+23+21+19+17+···+7+5+3+1=? 1/3*1+1/3*5+1/5*7+----1/17*19+1/19*21= 计算：1+3+5+7+9+11+13+15+17+19+21+23=______． 1+3+5+7+9+11+13+15+17+19+21+23+25+27+29=? (1+3)/1+(3+5)/1+(5+7)/1+(7+9)/1.+(17+19/1+(19+21)/1=? 2/1*3+2/3*5+2/5*7+.+2/17*19+2/19*21=? int a[3][4]={{1,3,5,7},{9,11,13,15},{17,19,21,23}}; *(*(a+2) int a[3][4]={{1,3,5,7},{9,11,13,15},{17,19,21,23}}; void main() { inta[3][4]={1,3,5,7,9,11,13,15,17,19,21,23}; i 1+3+5+7+9+11+13+17+19+21+23 1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31