(an+bn)/[根号下(an²+bn²)]=[1+(bn/an)]/根号下[1+(bn/an)
(an+bn)/[根号下(an²+bn²)]=[1+(bn/an)]/根号下[1+(bn/an)
已知数列an中,an=2倍根号下(an-1)设bn=lg(an/4)
若n∈N,(1+根号2)^n =(根号2)an + bn (an,bn∈Z)
各项和为正数的数列an和bn满足an,bn,an+1成等差数列,bn,an+1,bn+1成等比数列 求证(根号bn)是等
已知正数列{an}和{bn}满足:对任意n(n属于N*),an,bn,an+1成等差数列且an+1=根号下b
已知数列{an}、{bn}满足:a1=1/4,an+bn=1,bn+1=bn/1-an^2 (1)求{an}的通项公式
{an},{bn}中a1=2,b1=4,an,bn,an+1成等差数列bn,an+1,bn+1成等比数列(n∈N*)
数列an,bn各项均为正数,对任意n,an,bn,an+1成等差数列,bn,an+1,bn+1成等比数列证数列根号BN成
数列{an}和{bn}满足a1=1 a2=2 an>0 bn=根号an*an+1
求证极限:设数列{An},{Bn}均收敛,An=n(Bn-Bn-1),求证limAn = 0.
设An>0,级数An收敛,Bn=1-ln(1+An)/An,证明级数Bn收敛
设数列{an}满足a1=0,4an+1=4an+2根号(4an+1)+1,令bn=根号(4an+1)