sin(π/3-x)+cos(x+π/6)可化简为
sin(π/3-x)+cos(x+π/6)可化简为
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos平方x.
求证 tan(2π-X)sin(-2π-X)cos(6π-X)/ sin(X+3π/2)*cos(X+3π/2)=-ta
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=sin(2x-π/6) ,
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
求值:sin(π/4+3x)cos(3/π-3x)+cos(π/6+3x)cos(π/4+3x)
已知f(x)=3cos(x+3π2)+cos(x−3π2)+sin(x+π)+a(a∈R,a为常数).
已知函数为f(x)=cos(2x-π╱3)+2sin(x-π/4)sin(x+π/4)
f(x)=sin(x+a)+根号3cos(x+a),a属于(0,π)为偶函数 a=
sin(x-π/3)=1/3,则cos(x+π/6)=?
化简 sinx+sin(x+2π/3)+cos(x+5π/6)
化简(1)√3sin x+cos x (2)√2(sin x-cos x) (3)√2cos x-√6sin x