(1)(m²-3m)²n+2n(m²-2m)+n
化简m/(m+n)²+n/m²-n²-2n²/(m+n)(m²-n
【(m+n)(m-n)-(m-n²)+2n(m-n)】÷4n
化简-3(m-n)²-(m-n)平方-3(m-n)+4m-n)的平方+2(m-n)-1
(m+n)²+2(m+n)+1因式分解,
(m²-2m)²n+2n(m²-2m)+n
(1)(m²-3m)²n+2n(m²-2m)+n
设m等于1/5n求 2n/(m+2n)+m/(2n-m)+4mn/(4n²-m²)
把(m-n)当做一个整体,合并(m-n)²+2(m-n)-三分之一(n-m)²-3m+3n=____
因式分解:(m-n)²-(2n-m)²
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
先化简再求值:(2m-n)(m+n)+(m-n)²-(6m³-4m²n)÷2m,其中m=2