(1-sin^6 a-cos^6 a)/(sin^2 a-sin^4 a)的化简结果,
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(1-sin^6 a-cos^6 a)/(sin^2 a-sin^4 a)的化简结果,
(1-sin^6 a-cos^6 a)/(sin^2 a-sin^4 a)
=[1-(cos^6 a+sin^6 a)]/(sin^2 a-sin^4 a)
=[1-(cos^2a+sin^2a)(cos^4a-sin^2a*cos^2a+sin^4a)]/sin^2a(1-sin^2a)
=(1-cos^4a+sin^2a*cos^2a-sin^4a)/(sin^2a*cos^2a)
=[(1-cos^2a)(1+cos^2a)+cos^2asin^2a-sin^4a]/(sin^2a*cos^2a)
=[sin^2a+sin^2acos^2a+cos^2asin^2a-sin^4a]/(sin^2a*cos^2a)
=3sin^2acos^2a/(sin^2a*cos^2a)
=3
=[1-(cos^6 a+sin^6 a)]/(sin^2 a-sin^4 a)
=[1-(cos^2a+sin^2a)(cos^4a-sin^2a*cos^2a+sin^4a)]/sin^2a(1-sin^2a)
=(1-cos^4a+sin^2a*cos^2a-sin^4a)/(sin^2a*cos^2a)
=[(1-cos^2a)(1+cos^2a)+cos^2asin^2a-sin^4a]/(sin^2a*cos^2a)
=[sin^2a+sin^2acos^2a+cos^2asin^2a-sin^4a]/(sin^2a*cos^2a)
=3sin^2acos^2a/(sin^2a*cos^2a)
=3
(1-sin^6 a-cos^6 a)/(1-sin^4 a-cos^4 a)的化简结果
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
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