化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/10 16:09:50

=[1-(sin²a+cos²)(sin^4a-sin²acos²a+cos^4a)]/cos²a(1-cos²a)
=[1-(sin^4a+2sin²acos²a+cos^4a)+3sin²acos²a]/cos²asin²a
=[1-(sin²a+cos²a)²+3sin²acos²a]/cos²asin²a
=3cos²asin²a/cos²asin²a
=3

化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)== （1-sin^6a-cos^6a)/(1-sin^4a-cos^4a)=? 证明sin(4A)sin(2A)(1-cos(2A)) cos(4A)cos(2A)(1 cos(2A))=cos(2A 1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简化简1-sin^4a-cos^4a/1-sin^6a-cos^6a 化简 1-sin^4a-cos^4a/cos^2a-cos^4a 已知(4sin a－2cos a)／(5cos a +3sin a)=6/11,求cos＾4 a－sin＾4 a 证明Cos^A-Sin^A=1-2Sin^A=2Cos^A-1=cos^a-sin^a 若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a 化简[cos(a-π)/sin(π-a)]sin(a-π/2)cos(π/2+a)= 求值:1-sin^6a-cos^6a/1-sin^4a-cos^4a (1-sin^4a-cos^4a)/(1-sin^6a-cos^6a)