4(2y+3)+5(y-2)=8(1-y)
微分方程(1)(y'')^2+5y'-y+x=0;(2)y''+5y'+4y^2-8x=0;(3)(3x+2y)dx+(
求下列微分方程的通解或特解:(1) 3y''-2y'-8y=0 (2) 4y"-8y'+5y=0
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)
解3y+5/3y-6=1/2+5y-4/2y-4
解方程:(y+4)/5+y+6=(y+8)/2-(y+4)/3
1.5y+8y-6y=2y-3
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知y^2+3y-1=0求y^4/y^8+3y^4+1的值
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
解方程:4(2y+3)=8(1-y)-5(y-2) 解8y+3=8-y-5y+2 14y=7 所以y=1/2 错在:原因
(2y-3)(-y+4)=(y-2)(y-5)-3y(y-7/3)解方程