数列{an}满足a1=0且1/(1-an+1)-1/(1-an)=1.设bn=(1-根号an+1)/根号n,证明sn

设数列an满足a1=0且1/(1-an+1)-1/(1-an)=1,设bn=(1-根号an+1)/根号n,记Sn为bn的 设数列{an}满足a1=0,4an+1=4an+2根号(4an+1)+1,令bn=根号（4an+1） 数列{an}和{bn}满足a1=1 a2=2 an>0 bn=根号an*an+1 数列{an}和{bn}满足a1=1 a2=2 an>0 bn=根号an*an+1且{bn}是以公比为q的等比数列 设数列｛an}满足a1=2,an+1=an+1/an(n=1,2,3.),证明：an>根号下（2n+1).急用 已知数列an的n项和为Sn,且an+1=2Sn/an,a1=1 （1）求an (2)设数列bn满足（2an-1)(2bn 已知数列an满足;a1=1,an+1-an=1,数列bn的前n项和为sn,且sn+bn=2 已知数列{an}满足:an+an+1=2an+2,且a1=1,a2=2,n∈N* 一：设bn=an+1-an ,证明bn 已知数列{an}满足a1=1,a2=2,an+2=(an+an+1)/2,n∈N*.令bn=an+1-an,证明{bn} 数列{an}和{bn}中,a1=1,a2=2,an>0,bn=根号(an*a(n+1))(n为正整数),且{bn}是以q 数列an的前n项和为Sn=2^n-1,设bn满足bn=an+1/an,判断并证明bn 的单调性 数列an ,a1=1,当n>=2时,an=（根号sn+根号sn-1）/2,证明根号sn是等差数列,求an