设数列｛an}满足a1=2,an+1=an+1/an(n=1,2,3.),证明：an>根号下（2n+1).急用

设数列｛an}满足a1=2,an+1=an+1/an(n=1,2,3.),证明：an>根号下（2n+1).急用 设数列｛an｝满足an+1/an=n+2/n+1,且a1＝2 数列{an}满足a1=1 an+1=2n+1an/an+2n 设数列an满足a1=2 an+1-an=3-2^2n-1 已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an 已知数列{An}满足:A1=3 ,An+1=(3An-2)/An,n属于N*.1）证明：数列{（An--1）/（An-- 已知数列{an}满足：a1=3,an+1=（3an-2）/an ,n∈N*．（Ⅰ）证明数列{(an-1)/an-2 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 设数列{an}中,a1=2,an+1=an+n+1,则通项an=? 已知数列{an}满足a1=1,a2=2,an+2=(an+an+1)/2,n∈N*.令bn=an+1-an,证明{bn} 已知数列{An}满足A1=0.5,A1+A2+…+An=n^2An(n∈N*),试用数学归纳法证明:An=1/n(n+1