An=(-2-1/n2,1/n) lim n→∞ An=
lim(n2+2n+2)/(n+1)-an)=b,求a,b
请问如何证明lim(n→∞)[n/(n2+n)+n/(n2+2n)+…+n/(n2+nn)]=1,
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
lim(n到无穷) n2/n+1+an+b=0.a=?b=?
若lim[(2n-1)an]=1 求lim(n*an)的值
数列极限(已知lim[(2n-1)an]=2,求lim n*an)
已知数列an的前n项和Sn=(n^2+n)*3^n (1)求lim(n→∞)an/Sn (2).
lim(n2+1/n+1-an-b)=0,求a,b
lim (n→∞) (n^2/(an+b)-n^3/(2n^2-1))=1/4 求a,b
已知:lim (n→∞) [(n^2+n)/(n+1)-an-b]=1 ,求a,b的值
证明两个简单极限1、lim n→∞ n/[(n!)^(1/n)]=e2、an→A 求证:lim n→∞ (a1+2a2+
已知数列{an}满足lim[(2n-1)an]=2,则lim(n+2)an=