log(1/2) (x+1)>log(1/4) (3x+4)

1/log（2）x+1/log（3）x+1/log（4）x=1,x=? （高一）若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{lo y=log(4)(1-2x+x^2) =log(2)[(1-x)^2] /log(2)(4) =2[log(2)|1-x 化简:1/log(3)x 1/log(4)x 1/log(5)x=……(答案是1/log(60)x log的数学题2 + log 2（为底）4= 3x-1 已知log(1/7)[log(3)(log(2)x)]=0 log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) log(X+5)+log(X+2)=1 对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log( log(4)6能不能化简为log(2)3呢? 还有log(3)x=3分之1 x=多少 lg(7*2^x+8)>=log(√10) 2^x,求函数f(x)=log(1/2)x*log(1/2)x/4的最小值 对数不等式：log(1/2) (4x^2-x)>1