解不等式log(1/2)(x^2+2x-3)>log(1/2)(3x+1)
若不等式log(3-2x)
解不等式:√(log2(x-1))+log(1/2)(x^3)+2>0
1/log(2)x+1/log(3)x+1/log(4)x=1,x=?
解不等式:log½(x²-1)>log½(2x²-x-3)
解不等式log3(3^x-1)*log(3^(x+2)-9)
log底数7[log底数3(log底数2X)]=0,那么x^1/2的值是
解不等式:log∨3 (3+2x-x²)>log∨3 (3x+1)
请画出下列图像:log 1/2 (-x) y=log 1/3 /x/
(高一)若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{lo
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(
对数解不等式 ①log底数为1/3 真数(4x-6)大于等于2 ②log底数m真数(3x-4)大于3
解不等式log(0.5)(x2-5x-6)>log(2)(1/2(x+6))