化简:cos(π/3+α)+sin(π/6+α)
1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α)
化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)=
(1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π
化简:1、sin(x-π/3)-cos(x+π/6)+√3cosx=?2、已知,sinα+sinβ=√2/2,求cosα
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-
已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为
化简:sin(2π-α)cos(π/2+α)+sin(3π/2-α)cos(π-α)=
求证sin^2α+cosαcos(π/3+α)-sin^(π/6-α)的值与α无关
sin^2(α)+cosαcos(π/3+α)-sin^2(π/6-α)为定值,要证明
化简:sin^6α+cos^6α+3sin^2α*cos^2α=?
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
化简:sinα-√3 cosα+2cos(α-π/3)