化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)=

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/19 14:03:25

cos(π/6+α)=sin(π/3-α),sin(π/4+α)=cos(π/4-α)
所以,原式=sin(π/4-α)cos(π/3-α)-sin(π/3-α)cos(π/4-α)
=sin(π/4-α)cos(π/3-α)-cos(π/4-α)sin(π/3-α)
=sin[(π/4-α)-(π/3-α)]
=sin(-π/12)
=(√2-√6)/4

化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)= 已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为 1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α) 已知α∈（0,π/2),且2sinα-sinαcosα-3cosα=0.求[sin(α+π/4)]/[sin2α+cos 已知tan（π-α）=2,求sinα-2sinαcosα-cosα／4cosα-3sinα的值 α属于（0,π/2）且2sin²α-sinαcosα-3cos²α=0求sin(α+π/4)/sin 已知tan（α+π/4）=3,求cosα+2sinα/cosα-sinα的值已知tan(α+π/4)=2,则(2sinα+cosα)/(3cosα-2sinα) 已知tan(α+π/4)=2,求2cosα-sinα/cosα+3sinα 已知 sinα+2cos(5π/2+α)/cos(π-α)-sin(π/2-α)=-1/4 求(sinα+cosα)平方已知(3sinα+cosα)/(3cosα-sinα)=2,则2-3sin（α-3π）sin（1.5π-α）-[cos（已知sin a=2cos a 计算⑴（sinα+2cosα)/(5cosα-sinα) ⑵tan(α+π/4)