12x+24y=60 16*0.8x+27*0.8y=60
(x*x+y*y)(x*x+y*y)-(x*x+y*y)=12 求x*x+y*y等于多少
x,y,z分别代表三个不同的数,且X+X=x=y+y,y+y+y+y=z+z+z,x+y+y+z=60 ,那么Y+X+Z
x+y=450;40%x+30=60%y
函数y=x^(60/x)
{X+2Y/2+3X-Y/3=5{0.2(X+2Y)+0.8(3X-Y)=4
3(x+y)+2(x-y)=20 0.3x+0.6y=60 x=?y=?
已知实数x,y满足关系式5x+12y-60=0,则x
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
解方程组 x=3y-6 0.8(x+y)=x+y-13.6
x+y=127 0.5x+0.8y=83 求x和y
如果x和y成正比例,当x=16,y=0.8;如果x=10时,y是多少
2(x+y) 3x+3y=24 x+y/2x x y/2y= 1